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Clarify that the presence of a value with weight 1 is required
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@ -1252,7 +1252,7 @@ Number_of_Bits = Weight ? (Max_Number_of_Bits + 1 - Weight) : 0
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```
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When a literal value is not present, it receives a `Weight` of 0.
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The least frequent symbol receives a `Weight` of 1.
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Consequently, the `Weight` 1 is necessarily present.
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If no symbol has a `Weight` of 1, then the data is considered corrupted.
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The most frequent symbol receives a `Weight` anywhere between 1 and 11 (max).
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The last symbol's `Weight` is deduced from previously retrieved Weights,
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by completing to the nearest power of 2. It's necessarily non 0.
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