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Fix erroneous parsing of tsquery input "... & !(subexpression) | ..."
After parsing a parenthesized subexpression, we must pop all pending ANDs and NOTs off the stack, just like the case for a simple operand. Per bug #5793. Also fix clones of this routine in contrib/intarray and contrib/ltree, where input of types query_int and ltxtquery had the same problem. Back-patch to all supported versions.
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@ -189,8 +189,8 @@ makepol(WORKSTATE * state)
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case OPEN:
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if (makepol(state) == ERR)
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return ERR;
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if (lenstack && (stack[lenstack - 1] == (int4) '&' ||
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stack[lenstack - 1] == (int4) '!'))
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while (lenstack && (stack[lenstack - 1] == (int4) '&' ||
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stack[lenstack - 1] == (int4) '!'))
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{
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lenstack--;
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pushquery(state, OPR, stack[lenstack]);
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@ -234,8 +234,8 @@ makepol(QPRS_STATE * state)
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case OPEN:
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if (makepol(state) == ERR)
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return ERR;
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if (lenstack && (stack[lenstack - 1] == (int4) '&' ||
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stack[lenstack - 1] == (int4) '!'))
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while (lenstack && (stack[lenstack - 1] == (int4) '&' ||
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stack[lenstack - 1] == (int4) '!'))
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{
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lenstack--;
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pushquery(state, OPR, stack[lenstack], 0, 0, 0);
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@ -396,8 +396,8 @@ makepol(QPRS_STATE * state, void (*pushval) (QPRS_STATE *, int, char *, int, int
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case OPEN:
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if (makepol(state, pushval) == ERR)
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return ERR;
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if (lenstack && (stack[lenstack - 1] == (int4) '&' ||
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stack[lenstack - 1] == (int4) '!'))
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while (lenstack && (stack[lenstack - 1] == (int4) '&' ||
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stack[lenstack - 1] == (int4) '!'))
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{
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lenstack--;
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pushquery(state, OPR, stack[lenstack], 0, 0, 0);
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