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Reduce need for palloc/pfree overhead in varstr_cmp() by using fixed-size
buffers on stack for short strings.
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35223af057
commit
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@ -8,7 +8,7 @@
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*
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*
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*
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*
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* IDENTIFICATION
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* IDENTIFICATION
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* $Header: /cvsroot/pgsql/src/backend/utils/adt/varlena.c,v 1.92 2002/09/04 20:31:29 momjian Exp $
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* $Header: /cvsroot/pgsql/src/backend/utils/adt/varlena.c,v 1.93 2002/11/17 23:01:30 tgl Exp $
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*
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*
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*-------------------------------------------------------------------------
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*-------------------------------------------------------------------------
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*/
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*/
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@ -736,36 +736,47 @@ int
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varstr_cmp(char *arg1, int len1, char *arg2, int len2)
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varstr_cmp(char *arg1, int len1, char *arg2, int len2)
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{
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{
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int result;
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int result;
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char *a1p,
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*a2p;
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/*
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/*
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* Unfortunately, there is no strncoll(), so in the non-C locale case
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* Unfortunately, there is no strncoll(), so in the non-C locale case
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* we have to do some memory copying. This turns out to be
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* we have to do some memory copying. This turns out to be
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* significantly slower, so we optimize the case where LC_COLLATE is
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* significantly slower, so we optimize the case where LC_COLLATE is
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* C.
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* C. We also try to optimize relatively-short strings by avoiding
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* palloc/pfree overhead.
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*/
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*/
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#define STACKBUFLEN 1024
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if (!lc_collate_is_c())
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if (!lc_collate_is_c())
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{
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{
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a1p = (char *) palloc(len1 + 1);
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char a1buf[STACKBUFLEN];
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a2p = (char *) palloc(len2 + 1);
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char a2buf[STACKBUFLEN];
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char *a1p,
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*a2p;
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if (len1 >= STACKBUFLEN)
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a1p = (char *) palloc(len1 + 1);
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else
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a1p = a1buf;
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if (len2 >= STACKBUFLEN)
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a2p = (char *) palloc(len2 + 1);
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else
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a2p = a2buf;
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memcpy(a1p, arg1, len1);
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memcpy(a1p, arg1, len1);
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*(a1p + len1) = '\0';
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a1p[len1] = '\0';
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memcpy(a2p, arg2, len2);
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memcpy(a2p, arg2, len2);
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*(a2p + len2) = '\0';
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a2p[len2] = '\0';
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result = strcoll(a1p, a2p);
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result = strcoll(a1p, a2p);
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pfree(a1p);
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if (len1 >= STACKBUFLEN)
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pfree(a2p);
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pfree(a1p);
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if (len2 >= STACKBUFLEN)
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pfree(a2p);
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}
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}
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else
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else
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{
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{
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a1p = arg1;
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result = strncmp(arg1, arg2, Min(len1, len2));
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a2p = arg2;
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result = strncmp(a1p, a2p, Min(len1, len2));
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if ((result == 0) && (len1 != len2))
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if ((result == 0) && (len1 != len2))
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result = (len1 < len2) ? -1 : 1;
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result = (len1 < len2) ? -1 : 1;
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}
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}
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